Series & Summation Notation

Skill: series

Series & Summation Notation

From sigma notation to series formulas: expand and evaluate sums, and add up arithmetic and geometric series with confidence.

1 Reading sigma notation

The Greek letter Σ (sigma) is shorthand for “add them all up.” Every sigma has four parts.

Anatomy of a sum
∑k=mn ak  =  am + am+1 + … + an

k is the index (the counter), m the lower limit, n the upper limit, and ak the summand (the rule for each term). The number of terms is n − m + 1 — the index is not the term count.

Expand ∑k=25 (3k − 1)

k runs 2, 3, 4, 5 — that is 5 − 2 + 1 = 4 terms: (3·2−1) + (3·3−1) + (3·4−1) + (3·5−1) = 5 + 8 + 11 + 14 = 38.

2 Summing an arithmetic series

Pair the first term with the last, the second with the second-to-last — every pair sums to the same total.

Arithmetic series sum
Sn = n2(a1 + an) = n2(2a1 + (n − 1)d)

Use the left form when you know the last term an; use the right form when you know d. Both say the same thing: n copies of the average of the first and last terms.

Sum 4 + 7 + 10 + … + 61 (20 terms)

a1 = 4, d = 3, n = 20. S20 = 20/2 · (2·4 + 19·3) = 10 · (8 + 57) = 10 · 65 = 650.

3 Summing a geometric series

Multiply the whole sum by r, subtract, and almost everything cancels — leaving a clean formula.

Geometric series sum (r ≠ 1)
Sn = a1 · 1 − rn1 − r

The exponent is n here (not n − 1): the first term uses r0 = 1, so the sum runs through rn−1, and the formula carries one more power. If r = 1, every term equals a1 and Sn = n · a1.

Sum 2 + 6 + 18 + 54

a1 = 2, r = 3, n = 4. S4 = 2 · (1 − 34)/(1 − 3) = 2 · (1 − 81)/(−2) = 2 · 40 = 80.

4 Worked examples

Count, expand, and sum — each claim verified independently.

Example 1 Count the terms

How many terms does ∑k=310 ak have?

Terms: 10 − 3 + 1 = 8. The index starts at 3, so there are not 10 terms.

Example 2 Evaluate a sigma

Evaluate ∑k=15 (2k + 3).

Terms: 5, 7, 9, 11, 13. Sum = 45.

Example 3 Arithmetic sum from d

Find the sum of the first 20 terms with a1 = 4, d = 3.

S20 = 10 · (8 + 57) = 650.

Example 4 Arithmetic sum from an

An arithmetic series has a1 = 5, a10 = 50. Find S10.

S10 = 10/2 · (5 + 50) = 5 · 55 = 275.

Example 5 Geometric sum

Find the sum: a1 = 2, r = 3, n = 4.

S4 = 2(1 − 81)/(1 − 3) = 80.

Example 6 Geometric sum

Find the sum: a1 = 5, r = 2, n = 6.

S6 = 5(1 − 64)/(1 − 2) = 5 · 63 = 315.

Example 7 A single term of a sigma

In ∑k=18 k2, what is the value of the 4th term?

Substitute k = 4: 42 = 16.

5 Common mistakes

Two errors that break series problems.

Confusing the index with the number of terms

Wrong: ∑k=310 has 10 terms.
Right: count them: upper − lower + 1 = 10 − 3 + 1 = 8 terms.

Using n instead of n − 1 in the exponent for geometric series

Wrong: the first term of a1rn thinking.
Right: the first term uses exponent 0: a1 · r0 = a1. The nth term is a1rn−1; the sum formula carries rn.

6 Key vocabulary

Words to know

  • Sigma (Σ) notation — compact notation for a sum: index, limits, and summand.
  • Index — the counter variable (usually k); not the number of terms.
  • Partial sum (Sn) — the sum of the first n terms.
  • Arithmetic series — sum of an arithmetic sequence: Sn = n/2 · (a1 + an).
  • Geometric series — sum of a geometric sequence: Sn = a1(1 − rn)/(1 − r).

7 Quick check

Try these before moving on — click to reveal each answer.

How many terms are in ∑k=415 ak?
15 − 4 + 1 = 12 terms.
Evaluate ∑k=14 (3k − 2).
Terms: 1, 4, 7, 10. Sum = 22.
Find S5 for a1 = 3, r = 2 (geometric).
S5 = 3(1 − 32)/(1 − 2) = 3 · 31 = 93.

8 Next steps

Now drill the skill with endless randomized problems.

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