Derivatives

Skill: derivatives

Derivatives

Differentiate with the limit definition and the power rule, evaluate f′(a), and write tangent lines — with every step shown.

1 The derivative as a limit

The derivative is the limit of the slopes of secant lines as the second point slides into the first.

The definition
f′(x) = limh→0 [f(x + h) − f(x)] / h

The fraction is the slope between (x, f(x)) and (x + h, f(x + h)). Letting h → 0 squeezes the secant into the tangent — so f′(x) is the slope of the tangent line at x, i.e. the instantaneous rate of change.

Example f′(x) for f(x) = x² from the definition

[(x+h)² − x²]/h = [2xh + h²]/h = 2x + h → 2x as h → 0.

2 The power rule

The limit definition always works — but the power rule does it in one step.

The rules
d/dx [xn] = n·xn−1   (power rule)
d/dx [a·xn] = a·n·xn−1   (constant multiple)
d/dx [f + g] = f′ + g′   (sum rule)

Apply term by term: d/dx [3x² + 2x] = 6x + 2. Constants vanish: d/dx [7] = 0.

Example d/dx [4x³ − x]

12x² − 1 = 12x² − 1.

3 Tangent lines

The derivative at a point is the slope of the tangent line there.

Tangent line recipe
1. slope:   m = f′(a)
2. point:   (a, f(a))
3. line:   y − f(a) = m(x − a)

Never confuse f(a) (the height) with f′(a) (the slope): the point uses f, the slope uses f′.

Example Tangent to f(x) = x² at x = 3

f′(x) = 2x, so m = 6; f(3) = 9. Line: y − 9 = 6(x − 3), i.e. y = 6x − 9.

4 Worked examples

Each claim verified independently.

Example 1 Power rule

Find d/dx [x5].

5x4: 5x^4.

Example 2 Power rule, n = 1

Find d/dx [x].

1.

Example 3 Polynomial

Find d/dx [3x2 + 2x].

6x + 2: 6x + 2.

Example 4 Slope at a point

f(x) = 2x2. Find f′(3).

f′(x) = 4x; f′(3) = 12.

Example 5 Difference quotient

For f(x) = x2, simplify [f(x + h) − f(x)]/h.

2x + h (then h → 0 gives 2x).

5 Common mistakes

Three errors that break derivative work.

Forgetting to drop the exponent

Wrong: d/dx [x5] = 5x5.
Right: the power rule does two things — multiply by n and subtract 1 from the exponent: 5x4.

Using f(a) as the tangent slope

Wrong: tangent to x² at x = 3 has slope f(3) = 9.
Right: slope comes from the derivative: f′(3) = 6. The point (3, 9) uses f; the slope uses f′.

Leaving h in the final derivative

Wrong: from the definition, f′(x) = 2x + h.
Right: 2x + h is the difference quotient; the derivative takes h → 0, giving 2x.

6 Key vocabulary

Words to know

  • Difference quotient — [f(x + h) − f(x)]/h, the secant slope.
  • Derivative — f′(x): the limit of the difference quotient; tangent slope.
  • Tangent line — y − f(a) = f′(a)(x − a).
  • Power rule — d/dx [xn] = n·xn−1.

7 Quick check

Try these before moving on — click to reveal each answer.

Find d/dx [5x4 − 2x3 + 7].
20x3 − 6x2: 20x^3-6x^2.
f(x) = x3. Find the slope of the tangent line at x = 2.
f′(x) = 3x2; f′(2) = 12.
Write the tangent line to f(x) = x2 at x = 1.
m = 2, point (1, 1): y = 2x − 1.

8 Next steps

Now drill the skill with endless randomized problems.

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