Packets / Algebra 1 Essentials
Grades 8-10Algebra
Algebra 1 Essentials
The essential Algebra 1 toolkit: functions, linear equations and graphs, systems, polynomials, factoring, and quadratics. Worked examples in the Learn tab, instant-feedback practice, and a 60-second challenge.
1Functions and Function Notation
Key idea: A function is a rule that gives each input exactly ONE output. f(x), read 'f of x', is just a name for y.
- Read f(x) as 'f of x' — it is NOT f times x.
- To find f(a), replace every x in the rule with a.
- Compute carefully, watching the signs.
- The result is the output for input a.
Worked example
f(x) = 2x + 1, find f(3)
Replace x with 3: f(3) = 2(3) + 1 = 6 + 1 = 7. Input 3 gives output 7.
Worked example
f(x) = -3x + 5, find f(-2)
f(-2) = -3(-2) + 5 = 6 + 5 = 11. Watch the double negative: -3 times -2 is +6.
Watch out: The vertical line test: if any vertical line hits a graph twice, it is NOT a function — that x would have two outputs!
2Domain and Range
Key idea: The domain is all allowed inputs (x-values); the range is all outputs that actually come out (y-values).
- Domain: read LEFT to RIGHT — collect every x that appears.
- Range: read BOTTOM to TOP — collect every y that appears.
- List each value once (skip repeats).
- For graphs, the domain is how far the graph stretches horizontally, the range is how far it stretches vertically.
Worked example
{(0, 1), (2, 3), (4, 5)}
Domain: list the x-values: {0, 2, 4}. Range: list the y-values: {1, 3, 5}.
Worked example
f(x) = x2
You can square any real number, so the domain is all real numbers. Squares are never negative, so the range is y >= 0.
Watch out: Domain is about x (inputs), range is about y (outputs). Mixing them up is the classic mistake!
3Slope and Rate of Change
Key idea: Slope = rise / run = (y2 – y1) / (x2 – x1). Positive slope goes uphill, negative goes downhill, 0 is flat, undefined is vertical.
- Label the points (x1, y1) and (x2, y2).
- Compute the rise: y2 – y1 (change in y).
- Compute the run: x2 – x1 (change in x).
- Divide rise by run and simplify the fraction.
Worked example
Slope through (2, 5) and (6, 13)
m = (13 – 5) / (6 – 2) = 8 / 4 = 2. The line rises 2 for every 1 it runs.
Worked example
Slope through (1, 9) and (4, 3)
m = (3 – 9) / (4 – 1) = -6 / 3 = -2. The line falls 2 for every 1 it runs.
Watch out: Keep the ORDER: y2 – y1 over x2 – x1. Subtracting in a different order on top and bottom flips the sign! A vertical line has run = 0, so its slope is undefined.
4Slope-Intercept Form and Graphing Lines
Key idea: y = mx + b is the friendliest line equation: m is the slope, b is where the line crosses the y-axis. Plot b, then use the slope as rise over run.
- If the equation is not in y = mx + b form, solve for y first.
- Read m (slope) and b (y-intercept).
- Plot the y-intercept (0, b).
- From there, move by the slope (rise / run) to find a second point, then connect.
Worked example
y = 2x – 5
Compare with y = mx + b: m = 2 (slope), b = -5 (y-intercept). Plot (0, -5), then go up 2, right 1.
Worked example
Rewrite 2x + 5y = 20 in slope-intercept form
Subtract 2x: 5y = -2x + 20. Divide by 5: y = -25x + 4. Slope = -2/5, y-intercept = 4.
Watch out: A horizontal line y = number has slope 0, but a vertical line x = number has UNDEFINED slope — it can never be written as y = mx + b!
5Systems of Equations
Key idea: A system solution is the (x, y) point that makes BOTH equations true. Graph both lines: their crossing point is the answer.
- Graphing: draw both lines; the intersection point is the solution.
- Substitution: plug the expression for y from one equation into the other.
- Solve the one-variable equation for x, then plug back to find y.
- Check the point in BOTH original equations.
Worked example
y = x + 1 and y = -x + 5
Set equal: x + 1 = -x + 5. Add x: 2x + 1 = 5. Subtract 1: 2x = 4, so x = 2. Then y = 2 + 1 = 3. Solution: (2, 3).
Worked example
Solve by substitution: y = 3x – 2 and 2x + y = 8
Replace y: 2x + (3x – 2) = 8. Combine: 5x – 2 = 8. Add 2: 5x = 10, so x = 2. Then y = 3(2) – 2 = 4. Solution: (2, 4).
Watch out: Parallel lines never meet: NO solution. Same line twice: INFINITELY many solutions. Always verify your point in both equations!
6Polynomials: Add, Subtract, Multiply
Key idea: Add and subtract polynomials by combining like terms. Multiply two binomials with FOIL: First, Outer, Inner, Last.
- Adding: line up like terms and combine the coefficients.
- Subtracting: distribute the minus to EVERY term in the second polynomial, then combine.
- Multiplying binomials: FOIL — multiply First, Outer, Inner, Last.
- Combine the like middle terms and write the final answer.
Worked example
(3x2 + 5x – 2) + (x2 – 3x + 4)
Combine x2 terms: 3x2 + x2 = 4x2. Combine x terms: 5x – 3x = 2x. Constants: -2 + 4 = 2. Result: 4x2 + 2x + 2.
Worked example
(x + 3)(x – 5)
FOIL: x*x = x2, x*(-5) = -5x, 3*x = 3x, 3*(-5) = -15. Combine middles: x2 – 5x + 3x – 15 = x2 – 2x – 15.
Watch out: Subtraction is the danger zone: (5x^2 – 3x + 7) – (2x^2 – 3x + 1) becomes 5x^2 – 3x + 7 – 2x^2 + 3x – 1. The minus flips EVERY sign inside!
7Factoring in a Nutshell
Key idea: Factoring is un-multiplying. Always pull out the GCF first, then check for a quick trinomial pattern. This is a short tour — the Factoring Quadratics module covers every technique in full.
- Step 1: factor out the greatest common factor (GCF) if there is one.
- Step 2: for x2 + bx + c, find two numbers with product c and sum b.
- Step 3: write (x + first)(x + second).
- Step 4: check by FOIL — and keep factoring until nothing more works.
Worked example
6x2 + 9x
GCF of 6 and 9 is 3; smallest x-power is x. So 3x(2x + 3). Check: 3x(2x) + 3x(3) = 6x2 + 9x.
Worked example
x2 + 7x + 12
Need two numbers with product 12 and sum 7: 3 and 4. So (x + 3)(x + 4). Check with FOIL.
Watch out: This module only scratches the surface of factoring (GCF and simple trinomials). For difference of squares, perfect squares, the ac-method, and solving by factoring, work through the Factoring Quadratics packet module!
8Quadratic Functions and Graphing
Key idea: y = ax^2 + bx + c graphs as a parabola. If a > 0 it opens up (vertex is the minimum); if a < 0 it opens down (vertex is the maximum). Vertex x = -b / (2a).
- Identify a, b, c in y = ax2 + bx + c.
- Find the vertex x-coordinate: x = -b / (2a).
- Plug x back in to get the vertex y-coordinate.
- Plot the vertex, find the x-intercepts (zeros) by factoring if possible, and sketch the curve.
Worked example
y = x2 – 4x + 3: find the vertex and zeros
Vertex x = -b / (2a) = 4 / 2 = 2. Plug in: y = 4 – 8 + 3 = -1. Vertex: (2, -1). Factor: (x – 1)(x – 3) = 0, so the graph crosses the x-axis at x = 1 and x = 3.
Worked example
y = -2x2 + 8x – 6: which way does it open?
a = -2, which is negative, so the parabola opens DOWNWARD — the vertex is the highest point.
Watch out: The vertex is a MINIMUM when a > 0 and a MAXIMUM when a < 0. Do not mix them up! The parabola is symmetric: the zeros sit the same distance left and right of the vertex x-value.
9Exponent Rules Review
Key idea: Same base: multiply = add exponents, divide = subtract exponents. Power of a power = multiply exponents. Different bases = leave them alone.
- Check the bases match — no matching base, no rule.
- Multiplying powers: add the exponents.
- Dividing powers: subtract the exponents.
- Power of a power: multiply the exponents. Power of a product: distribute the power to every factor.
Worked example
x3 * x5
Same base: ADD exponents. x3 * x5 = x^(3+5) = x8.
Worked example
(2x4)2
Power of a product: raise EACH part. 22 = 4 and (x4)2 = x8. Result: 4x8.
Watch out: You can only combine exponents when the BASES are the same: x^3 * y^5 cannot simplify! And (x^3)^2 = x^6, not x^9 — power of a power MULTIPLIES the exponents.
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60-Second Challenge
How many algebra 1 essentials problems can you solve in 60 seconds?